Question

in figure 15b show that AB is parallel to EF​

Answer 1

Answer:

I have proved it.

Explanation:

Done using interior angles test and alternate angles test.

Answer 2

Explanation:

$sol {}^{n}$

<BCD = <BCD + <ECD

= 33°+32°

= 65°

So, <BCD = <ABC = 65°

Hence , AB || CD (Alternate angles are equal)

Again ,

<FEC + <+ECD = 148° + 32°

= 180°

But these are co interior angles produced by the transversal CE intersecting EF & CD

So, EF || CD

Thus we see that AB|| CD & EF || CD

Hence AB || EF