Question

In figure 2.18, ZQPR = 90°,
seg PMI seg QR and Q-M-R,
PM = 10, QM = 8, find QR

PLZZZ ANSWER

ITS VERY URGENT!!!!!​

Answer 1

Answer:

Hence, QR = 20.5

Step-by-step explanation:

In a right angled triangle, the perpendicular segment to the hypotenuse from the opposite vertex, is the geometric mean of the segments into which the hypotenuse is divided.

Here, seg PM ⊥ seg QR

∴ PM²=QM×MR

⇒10²=8×MR

⇒100=8×MR

⇒MR=100/8

⇒MR=25/2

Now,QR=QM+MR

=8+25/2

=16+25/2

=41/2

=20.5

Hence, QR = 20.5