In figure 2.21, if ray BA || ray DE,∠C=50° and ∠D=100°. Find the measure of ∠ABC.(Hint : Draw a line passing through point C and parallel to line AB.)
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Answer:
∠ABC = 130°
Step-by-step explanation:
Let draw a line Parallel to BA & DE passing through C
Line is PQ passing through C
PQ || BA || DE
∠DCP = ∠CDE
=> ∠DCP = 100°
∠DCP + ∠DCQ = 180°
100° + ∠DCQ = 180°
∠DCQ = 80°
∠PCB = ∠DCQ + ∠DCB
=> ∠PCB = 80° + 50°
=> ∠PCB = 130°
∠ABC = ∠PCB
=>∠ABC = 130°
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