In figure 2.22, ray AE || ray BD, ray AF is the bisector of ∠EAB and ray BC is the bisector of ∠ABD. Prove that line AF || line BC.
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In figure 2.22, ray AE || ray BD, ray AF is the bisector of ∠EAB and ray BC is the bisector of ∠ABD.
Proved that line AF || line BC.
Step-by-step explanation:
ray AE || ray BD
∠BAE = ∠ABD
=> ∠BAF + ∠EAF = ∠ABC + ∠DBC
=> x + x = y + y
=> 2x = 2y
=> x = y
∠BAF = x
∠ABC = y
=> ∠BAF = ∠ABC
AF ║ BC
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