In figure 2.28, line PS is a transversal
of parallel line AB and line CD. If Ray
QX, ray QY, ray RX, ray RY are angle
bisectors, then prove that QXRY is a
rectangle.
Answers
Given :
Two parallel lines AB and CD are intersected by a Transversal PR in points Q and R respectively.
The bisectors of two pairs of interior angles intersect in Y and X.
To prove:
QXRY is a rectangle.
Proof :
and a Transversal QR intersects them
< AQR = <QRD
( Alternate interior angles )
( Halves of equals are equal )
=> <1 = <2
But these form a pair of equal alternate interior angles.
Similarly , we can show that
/* From (1) and (2) , */
QYRX is a parallelogram.
Now, The sum of consecutive interior angles on the same side of a Transversal is 180° .
In ∆QRY ,
/* Angle sum Property */
/* A parallelogram with one of its angles of measure 90° is a rectangle. */
•••♪
Given :
Two parallel lines AB and CD are intersected by a Transversal PR in points Q and R respectively.
The bisectors of two pairs of interior angles intersect in Y and X.
To prove:
QXRY is a rectangle.
Proof :
and a Transversal QR intersects them
< AQR = <QRD
( Alternate interior angles )
( Halves of equals are equal )
=> <1 = <2
But these form a pair of equal alternate interior angles.
Similarly , we can show that
From (1) and (2) ,
QYRX is a parallelogram.
Now, The sum of consecutive interior angles on the same side of a Transversal is 180° .
In ∆QRY ,
/Angle sum Property.
A parallelogram with one of its angles of measure 90° is a rectangle.