In figure 2.30, point T is in the interior of rectangle PQRS, Prove that, TS? + TQ2 = TP2 + TR2 (As shown in the figure, draw seg AB || side SR and A-T-B).
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In the adjoining figure, point T is in the interior of rectangle PQRS. Prove that, TS2 + TQ2 = TP2 + TR2 . (As shown in the figure, draw seg AB || side SR and A – T – B)
Given: \(\Box\)PQRS is a rectangle. Point T is in the interior of PQRS. To prove: TS2 + TQ2 = TP2 + TR2 Construction: Draw seg AB || side SR such that A – T – B.
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