Question

In Figure 2, AB and AC are tangents to the circle with centre O such that ∠BAC = 40°. Then ∠BOC is equal to
A. 40°
B. 50°
C. 140°
D. 150

Answer 1

your answer is here ✌✌✌✌✌

Answer 2

Answer:

The raddi to the tangents of contact make right and so the sum of the two angles will be 180°

In a quadrilateral the sum of the angles is 360°

so the other two angles add up to 180°

∠ACO =  ∠ABO = 90°

find  ∠BOC = ?

∵∠BAC = 40°

∠BAC +∠BOC  = 180°

∠BOC = (180° 40°)

∠BOC = 140°

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@GauravSaxena01