In Figure-2, ABC is an isosceles
s triangle, right-angled at C. Therefore
(A), AB2=2AC2
(B) BC2 = 2AB2
(C) AC2 = 2AB2
(D) AB2= 4AC2
AC AAC
AB²
(2A CZ
Figure-2
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Answer:
(A), AB^2=2*AC^2.
Explanation:
By Pythagoras theorem,
AB^2=AC^2 + BC^2
AB^2=AC^2 + AC^2 [BC=AC, ISOCELES TRIANGLE]
AB^2=2*AC^2[PROVED]
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