Question

in figure 2, ABCD is a trapezium which AB || CD. Find the value of x and y​

Answer 1

Answer:

Solution

In trapezium ABCD,

AB || CD

∴

∠

A

+

∠

D

=

180

∘

(Sum of cointerior angles)

x

+

20

∘

+

2

x

+

10

∘

=

180

∘

3

x

+

30

x

∘

=

180

∘

⇒

3

x

=

180

∘

−

30

∘

3

x

=

150

∘

x

=

150

∘

3

=

50

∘

Similarly,

∠

B

+

∠

C

=

180

∘

⇒

y

=

92

∘

=

180

∘

⇒

y

=

180

∘

−

92

∘

=

88

∘

∴

x

=

50

∘

,

y

=

88

∘

Answer 2

Answer:

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