In Figure-2, PQ is tangent to the circle with centre at 0, at the point B. If
_ AOB = 100°, then _ ABP is equal to
A 50°
B) 40°
C 60°
D 80°
Figure-2
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OA=OB [RADII]
ang OBA=ang OAB=30 deg [angles opp. to equal sides are equal]
ang OPB=90 deg [tangent]
ang OBA+ang ABP=90
30+ang ABP=90
ang ABP=90-30=60 deg
ang AOB= 180-(30+30)
120 [angle sum property of triangle]
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