Math, asked by sbta59gmailcom, 11 months ago

In Figure-2, PQ is tangent to the circle with centre at 0, at the point B. If
_ AOB = 100°, then _ ABP is equal to
A 50°
B) 40°
C 60°
D 80°
Figure-2​

Answers

Answered by deepakshigoyat19
2

\bf\huge\underline\red{Answer}

OA=OB [RADII]

ang OBA=ang  OAB=30 deg [angles opp. to equal sides are equal]

ang OPB=90 deg [tangent]

ang OBA+ang ABP=90

30+ang ABP=90

ang ABP=90-30=60 deg

ang AOB= 180-(30+30)

                  120  [angle sum property of triangle]

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