Question

In Figure 2,
the bisectors of Angle (A) and Angle (B) meet at point P. If Angle (C) = 50° and Angle (D) = 100°, find the measure of Angle (APB).​

Answer 1

As we know that the sum of all the angles of a quadrilateral is 360°

So,DAB +CBA = 360-150= 210

Then,

1)/2 DAB + 1/2 CBA = 210/2=105

So,the value of APB is 105

Answer 2

Answer:

Angle APB=75°

Step-by-step explanation:

As we know that sum of all the angles of a quadrilateral is 360 .

Let angle a and b be x and y respectively. So,

100+50+x+y=360

X+Y=360-150

x+y=210.

As APB is an triangle so sum of all the angles of a triangle is supplementary.

But a and b are bisected so

1/2×210=105

a+b+p=180

105+p=180(since,value of a,b collectively is 105)

P=75

Angle APB=75°