In figure 2, the bisectors of angle A and B meets at point P. If angle C =50° and D =100°, find the measure of angle APB.
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let angle DAP=BAP=x °
let angle CBP=PBA=y°
By angle sum property of a quadrilateral,
2x+2y+100°+50°=360°
2(x+y)=210°
x+y=105°
By angle sum property in traingle APB,
x+y+angle APB=180°
Angle APB=180°-105°
=75°
kunalSingh0403:
Thank you very much.
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