Question

In figure 3.28, ABCD is a parallelogram and the line segments AP and CQ bisect the angles A and C respectively. Show that AP || CQ
plz sove step by step​

Answer 1

Answer:

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Answer 2

Answer:

when PAQC is parallelogram then PA//QC

(due to lack of space i not able to show your fig and last line of answer)

Step-by-step explanation:

opp. angle of //gm are equal so ang. BAD=BCD

multiple both angle by 1/2 then ang. PAQ=QCA

in quad. PAQC PC//AQ and ang. PAQ=QCA

so PAQC is quad. whose opp. angle are equal and opp. side are parallel

so, PAQC is //gm.

PA//QC (side of llgm)

hence proved