In figure 3.48, point A is on the bisector of <XYZ.
If <X = 2 cm then find< Z.
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Ay is the bisector of <xyz
so, <ayx = <ayz .......(1)
In tri.ayx and tri.ayz
<axy = < azy (each of 90°)
Ay =Ay (common )
<ayx = <ayz (from eq.1 )
tri.ayx is congruent tri.ayz (AAS similarity )
AX = AZ ( By C.P.C.T.C )
AX =2 cm
and AX =AZ = 2 CM
HENCE ,AZ = 2 Cm
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Answer:
<x = 2 ✅
<Z = 2 ........[as per angle bisector theorem]
°•° triangle YXA congruent to triangle XZA .....{sss test of congruence}
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