In figure 3.98. seg AB is a diameter of
a circle with centre 0. The bisector
ACB intersects the circle at point D.
Prove that seg AD 3 seg BD.
Complete the following proof by filling
in the blanks
Proof Draw seg OD.
Fig. 3.98
2 ACB = .......... angle inscribed in semicircle
DCB = ...... CD is the bisector of 2C
mi arc DB) = .......... inscribed angle theorem
DOB = .......... definition of measure of an arc (1)
seg OA seg OB ..........
line OD is of seg AB .......... From (1) and (II)
seg AD seg BD
Answers
Step-by-step explanation:
∠ACB = 90°................angle inscribed in semicircle
∠DCB = 45°.................CD is the bisector of ∠C
m (arc DB) = 90° ...........Inscribed angle theorem
∠DOB = 90°.................. definition of the measure of an arc (i)
seg (OA) ≅ seg (OD)............Radius of the circle (II)
∴ line OD is Perpendicular bisector of seg AB ...........From (I) and (ii)
∴ seg AD ≅ seg BD
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