In Figure 3, a right triangle ABC, circumscribes a circle of radius r. If AB and BC are of lengths of 8 cm and 6 cm respectively, find the value of r.
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Given ,
AB =8cm , BC=6cm
In rt. triangle ABC,
AC^2 = AB^2 + BC^2
= (8)^2 + (6)^2
= 64 + 36
= 100
AC =10 cm ,
here , radius of circle = hypotenuse /2
= 10/2 = 5cm
AB =8cm , BC=6cm
In rt. triangle ABC,
AC^2 = AB^2 + BC^2
= (8)^2 + (6)^2
= 64 + 36
= 100
AC =10 cm ,
here , radius of circle = hypotenuse /2
= 10/2 = 5cm
EdwardCullen12:
how come radius of the circle is half the length of hypotenuese?
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