Question

in figure 39 ABCD is a rectangle if angle CEB : angle ECB=3:2 find the measure of

i) angle ECB
ii) angle AEC




Please answer as soon as possible

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Answer 1

Step-by-step explanation:

From the question it is given that,

ABCD is a rectangle∠CEB:∠ECB=3:2

We have to find,

(i) ∠CEB and

(ii) ∠DCF

Consider the ΔBCE

∠B=90

∘

Therefore, ∠CEB+∠ECB=90

∘

Let us assume the angles be 3 y and 2y

3y+2y=90

∘

5y=90

∘

y=90

∘

/5

y=18

∘

Then, ∠CEB=3y=3×18=54

∘

∠CEB=∠ECD

54

∘

=54

∘

... [alternate angles are equal]

We know that, sum of linear pair angles equal to 180

∘

∠ECD+DCF=180

∘

54

∘

+∠DCF=180

∘

By transposing we get, ∠DCF=180

∘

−54

∘

∠DCF=126

∘

Answer 2

Answer:

REFER IN THE ATTACHMENT