Question

In Figure 4, ABCD is a parallelogram in which angle ADC = 60° and angle ACB = 70°. Find the
measures of angle DCB, angle CAB and angle DAC​

Answer 1

Answer:

Given =ADC=60°, ACB=70°

FIND= measure of angle DCB, angle CAB

and angle DAC

SOLUTION= As given ADC is to 60° and angle ACB is to 70°

DCA+ACB=180°

DCA+70°=180°

DCA=180°-70°

DCA=110°

sum of a triangle,

DAC+DCA+ADC=180°

DAC+110°+60°=180°

DAC=180°-110°-60°

DAC=10°

DAC+CAB=180°

10°+CAB=180°

CAB=180°-10°

CAB=170°