In figure 5. 10,if AC=BD,then prove that AB=CD
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=> AC=BD
=> AC-BC=BD-BC(If equal are subtracted from
equal then the whole is equal.)
=> AB=CD
PROVED
=> AC-BC=BD-BC(If equal are subtracted from
equal then the whole is equal.)
=> AB=CD
PROVED
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AC=BD. ( 1)
AC=AB+CD. (B lies on between A and C. (2)
BD=BC+CD. ( 3)
From 2 and 3 in 1 gets
AB+BC=BC+CD
AB=CD
AC=AB+CD. (B lies on between A and C. (2)
BD=BC+CD. ( 3)
From 2 and 3 in 1 gets
AB+BC=BC+CD
AB=CD
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