Question

In Figure-5, a tent is in the shape of a cylinder surmounted
top. The cylindrical part is 2.1 m high and conical part has slant height
2.8 m. Both the parts have same radius 2 m. Find the area of the canvas used to make the tent. (Use π= 22/7)​

Answer 1

area of canvas used=curved surface area of cone+curved surface area of cylinder.

curved surface area of cone=>πrl=22/7×2×2.8=17.6(m)2

curved surface area of cylinder=>2πrh=2×227×2×2.1=26.4(m²

total surface area=26.4+17.6=44(m)2.

Answer 2

area of the canvas used to make the tent is 44 m ²

Step-by-step explanation:

radius of cone and cylinder(r) = 2 m

height of the cylinder(h)= 2.1 m

slant height of the cone (l)= 2.8 m

area of the canvas = CSA of cone + CSA of cylinder

area of the canvas = $\pi r l + 2 \pi rh$

$= \frac{22}{7} \times 2 \times 2.8+2 \times \frac{22}{7}\times 2\times 2.1\\\\= \frac{22}{7} \times 2(2.8+ 2 \times 2.1)\\\\= \frac{22}{7} \times 2(2.8+4.2)\\\\= \frac{22}{7} \times 2\times 7\\\\= 44$

hence , area of the canvas used to make the tent is 44 m ²

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A tent is in the shape of a cylinder surmounted by a conical top of same diameter

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