Question

In figure 5, AB || CD. If angle BAE = 110°, and angle DCE = 118°, find the value of x.
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Answer 1

Required Answer:-

Draw a parallel line to AB and ED from E to X. As it is given in the question, AB || CD. Now identify the pair of supplementary and interior angles which will add upto 180°. Because AE and EC are the transversal between them lines AB & EX and EX & CD respectively$.$

Then,

• < BAE + < AEX = 180°
• < XEC + < ECD = 180°

Now plug the measures of angles <BAE and <ECD. And we will get:

• < AEX = 180° - 110° = 70°
• < XEC = 180° - 118° = 62°

As, we know:

Angle x is the sum of <AEX and <XEC, the measure of angle x will be 70° + 62° = 132° (Ans)

Answer 2

Answer:

Required Answer:-

Draw a parallel line to AB and ED from E to X. As it is given in the question, AB || CD. Now identify the pair of supplementary and interior angles which will add upto 180°. Because AE and EC are the transversal between them lines AB & EX and EX & CD respectively..

Then,

< BAE + < AEX = 180°

< XEC + < ECD = 180°

Now plug the measures of angles <BAE and <ECD. And we will get:

< AEX = 180° - 110° = 70°

< XEC = 180° - 118° = 62°

As, we know:

Angle x is the sum of <AEX and <XEC, the measure of angle x will be 70° + 62° = 132° (Ans)