in figure 5 ABCD is a parallelogram.find the value of a,b,c and d
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97
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in the triangle BCD the sum of all the angles is equal to 180 degrees
therefore,
3a+7a+2a=180
12a=180
a =180/12
a= 15
(I. e) 3a= 3(15)= 45
7a=7(15)=105
2a=2(15) =30
therefore angle A=angle C
( OPP. angles of a parallelogram are equal)
=> angle B = angle D
(OPP. angles of a parallelogram are equal)
therefore, 7a=c
=> c= 105
in a parallelogram OPP. sides are parallel and equal
therefore, AB is parallel to CD
and BD is a transversal
therefore angle d=2a
(alternate interior angles are equal)
=> d= 30
and also b=3a
(alternate interior angles are equal)
=> b= 45
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I hope this might helped you
please mark as brainlist answer
---------------------@vishnu1123------------------------
kindly vishnu
thank you
in the triangle BCD the sum of all the angles is equal to 180 degrees
therefore,
3a+7a+2a=180
12a=180
a =180/12
a= 15
(I. e) 3a= 3(15)= 45
7a=7(15)=105
2a=2(15) =30
therefore angle A=angle C
( OPP. angles of a parallelogram are equal)
=> angle B = angle D
(OPP. angles of a parallelogram are equal)
therefore, 7a=c
=> c= 105
in a parallelogram OPP. sides are parallel and equal
therefore, AB is parallel to CD
and BD is a transversal
therefore angle d=2a
(alternate interior angles are equal)
=> d= 30
and also b=3a
(alternate interior angles are equal)
=> b= 45
-----------------------------------------------------------------
I hope this might helped you
please mark as brainlist answer
---------------------@vishnu1123------------------------
kindly vishnu
thank you
Vishnu1123:
plz mark me
Answered by
47
so this is the solution .
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