Question

In Figure 5 , ABCD is a rectangle b. If <CEB : <ECB = 3:2 , Find the measure of I) < ECB. 2) < AEC​

Answer 1

Answer:

Step-by-step explanation:

Angle DEF =126

THEREFORE,,, FCB=360-126-90 (ANGLE IN REC.ARE OF 90')

=144'

Let angleCEB =3x and ECB BE 2x

and

Angle BCF =CEB +EBC

144=3x +2x

144 =5x

x= 144/5

x = 28.8

Therefore, CEB = 3×28.8

=86.4

EBC= 2×28.8

=57.6

And, Angle AEC+CEB =180(LINEAR PAIR)

AEC+ 86.4=180

AEC=180-86.4

=93.6

Answer 2

Answer:

answer in attachment

@dachu515151

Step-by-step explanation:

-----