Question

In figure 5,ABCD is a rectangle. If angleCEB:angleECB = 3:2,find the measure of 1.angle ECB 2.angle AEC​

Answer 1

Answer:

angle ECB=36°

angle AEC = 126

Step-by-step explanation:

DC||AB hence by corresponding angle AEC=DCF

AEC=126°..........................{1}

angle ECF = 180°{straight line}

angle DCF+DCE=angle ECF

126°+DCE=180°

DCE=54°...........................{2}

angle ECB+DCE=90°(angle of rectanle =90°)

ECB+54°=90° {from 2}

ECB= 36°