Question

In figure .6.100. Find the value of x
Plzz solve this i need the answer urgently

Answer 1

angleEBD+angle DBC+ angleCBF=180

x+3+x+20+x+7=180 (straight line)

3x+30=180

3x=150

x=50

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Answer 2

Answer:

( X+ 3 )° ( X+ 20 )° ( X+7 )° = 180° ( angles on a straight line )

X ( 3+20+7 )° = 180°

3x° + 20x° + 7x° = 180°

30x° = 180°

X = 180/30°

X =6°