In figure 6.29,ifAB//CD,CD//EF and Y:Z,-3:7 find x
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Given that y : z = 3 : 7
Let ∠ y = 3a
Then ∠z = 7a
∠x and ∠z are alternate interior angles of parallel lines so that
∠x = ∠z …(1)
Sum of interior angle on the same side of the transversal is always = 180°
So that
x + y = 180°
plug the value of x from equation (1)
z + y = 180°
plug the value of z and y we get
7a + 3a = 180°
10 a = 180°
a = 180°/10
a = 18
y = 3a = 3x18 = 54°
z = 7a = 7x18 = 126°
x = z = 126°
hope u helpul
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