in figure 6.70, side BC of triangle ABC is produced to D such that angle ACD=70 degrees. if angle BAC=10 degrees find the angle ABC and angle ACB
Answers
Answered by
10
Answer:
Search for questions, posts and chapters
Maths
Bookmark
In the given figure, side BC of △ABC is produced to D. If ∠ACD=128
∘
, and ∠ABC=43
∘
, find ∠BAC and ∠ACB.
1715847
expand
share
Share
Answer
From the figure we know that ∠ACB and ∠ACD form a linear pair of angles
So we get
∠ACB+∠ACD=180
∘
By substituting the values
∠ACB+128
∘
=180
∘
On further calculation
∠ACB=180
∘
−128
∘
By subtraction
∠ACB=52
∘
We know that the sum of all the angles in a triangle is 180
∘
.
So we can write it as
∠ABC+∠ACB+∠BAC=180
∘
By substituting the values
43
∘
+52
∘
+∠BAC=180
∘
On further calculation
∠BAC180
∘
−43
∘
−52
∘
By subtraction
∠BAC=180
∘
−95
∘
∠BAC=85
∘
Therefore, ∠BAC=85
∘
and ∠ACB=52
∘
.
Similar questions
Science,
22 days ago
Math,
22 days ago
Business Studies,
1 month ago
Chemistry,
9 months ago
Hindi,
9 months ago