Math, asked by csailaja83, 1 month ago

in figure 6.70, side BC of triangle ABC is produced to D such that angle ACD=70 degrees. if angle BAC=10 degrees find the angle ABC and angle ACB​

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Answered by llAujlaUstaadll
10

Answer:

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In the given figure, side BC of △ABC is produced to D. If ∠ACD=128

, and ∠ABC=43

, find ∠BAC and ∠ACB.

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Answer

From the figure we know that ∠ACB and ∠ACD form a linear pair of angles

So we get

∠ACB+∠ACD=180

By substituting the values

∠ACB+128

=180

On further calculation

∠ACB=180

−128

By subtraction

∠ACB=52

We know that the sum of all the angles in a triangle is 180

.

So we can write it as

∠ABC+∠ACB+∠BAC=180

By substituting the values

43

+52

+∠BAC=180

On further calculation

∠BAC180

−43

−52

By subtraction

∠BAC=180

−95

∠BAC=85

Therefore, ∠BAC=85

and ∠ACB=52

.

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