In figure 6.73 ab parallel cd angle abe is 20 degree and angle ecd is 70 degree find angle bec.
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is this figure correct.
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Answer = <BEC = 130°
Step-by-step explanation:
Given = AB || CD , <ABE =20° , < ECD = 70°
To Find = <BEC
Construction = Draw a line EF || AB and CD passing through <E
Prove = < ABE = < BEF ( Alternate interior angles)
20° = < BEF
< FEC + < ECD = 180° ( Co-interior angles)
<FEC + 70° = 180°
<FEC = 180° - 70°
< FEC = 110°
Hence , < BEF + < FEC = <BEC
20° + 110° = <BEC
130° = < BEC
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