in figure 6 AB is equal to AD and angle BAC is equal to angle DAC prove that line segments CA bisects angle BCD
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Given→AD=AB , ∠BCA=∠DAC
To prove→CA bisect ∠BCD or we can say ∠BCA=∠DCA
proof→in ∆ ABC and ∆ ADC
AB=AD(given)
AC=AC(common)
∠BAC=∠DAC(given)
so,∆ ABC≈∆ ADC(SAS)
and, ∠BCA=∠DCA(CPCT)
hence,proved.
hope it helps........
@#opeless
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