Math, asked by mohitbhangale203, 3 months ago

In figure 6, ABCD is a parallelogram where, CE is perpendicular to AB produced and BF is perpendicular to AD. if ab =20 cm,ad=16cm and CE=10cm, then find bf

Answers

Answered by crackmehkma7172
0

Answer:

At first,

At first,Area of parallelogram = 1/2 × base × altitude

At first,Area of parallelogram = 1/2 × base × altitudeArea = 1/2 × AB × CE

At first,Area of parallelogram = 1/2 × base × altitudeArea = 1/2 × AB × CEArea = 1/2 × 30 × 14

At first,Area of parallelogram = 1/2 × base × altitudeArea = 1/2 × AB × CEArea = 1/2 × 30 × 14★Area = 210 {cm}^{2}Area=210cm

At first,Area of parallelogram = 1/2 × base × altitudeArea = 1/2 × AB × CEArea = 1/2 × 30 × 14★Area = 210 {cm}^{2}Area=210cm 2

At first,Area of parallelogram = 1/2 × base × altitudeArea = 1/2 × AB × CEArea = 1/2 × 30 × 14★Area = 210 {cm}^{2}Area=210cm 2 ★

At first,Area of parallelogram = 1/2 × base × altitudeArea = 1/2 × AB × CEArea = 1/2 × 30 × 14★Area = 210 {cm}^{2}Area=210cm 2 ★Secondly,

At first,Area of parallelogram = 1/2 × base × altitudeArea = 1/2 × AB × CEArea = 1/2 × 30 × 14★Area = 210 {cm}^{2}Area=210cm 2 ★Secondly,Area of parallelogram= 1/2 × base × altitude

At first,Area of parallelogram = 1/2 × base × altitudeArea = 1/2 × AB × CEArea = 1/2 × 30 × 14★Area = 210 {cm}^{2}Area=210cm 2 ★Secondly,Area of parallelogram= 1/2 × base × altitudeArea = 1/2 × AD × BF

At first,Area of parallelogram = 1/2 × base × altitudeArea = 1/2 × AB × CEArea = 1/2 × 30 × 14★Area = 210 {cm}^{2}Area=210cm 2 ★Secondly,Area of parallelogram= 1/2 × base × altitudeArea = 1/2 × AD × BFArea = 1/2 × AD × 20

At first,Area of parallelogram = 1/2 × base × altitudeArea = 1/2 × AB × CEArea = 1/2 × 30 × 14★Area = 210 {cm}^{2}Area=210cm 2 ★Secondly,Area of parallelogram= 1/2 × base × altitudeArea = 1/2 × AD × BFArea = 1/2 × AD × 20★Area = 10AD{cm}^{2}Area=10ADcm

At first,Area of parallelogram = 1/2 × base × altitudeArea = 1/2 × AB × CEArea = 1/2 × 30 × 14★Area = 210 {cm}^{2}Area=210cm 2 ★Secondly,Area of parallelogram= 1/2 × base × altitudeArea = 1/2 × AD × BFArea = 1/2 × AD × 20★Area = 10AD{cm}^{2}Area=10ADcm 2

At first,Area of parallelogram = 1/2 × base × altitudeArea = 1/2 × AB × CEArea = 1/2 × 30 × 14★Area = 210 {cm}^{2}Area=210cm 2 ★Secondly,Area of parallelogram= 1/2 × base × altitudeArea = 1/2 × AD × BFArea = 1/2 × AD × 20★Area = 10AD{cm}^{2}Area=10ADcm 2 ★

At first,Area of parallelogram = 1/2 × base × altitudeArea = 1/2 × AB × CEArea = 1/2 × 30 × 14★Area = 210 {cm}^{2}Area=210cm 2 ★Secondly,Area of parallelogram= 1/2 × base × altitudeArea = 1/2 × AD × BFArea = 1/2 × AD × 20★Area = 10AD{cm}^{2}Area=10ADcm 2 ★Equaling both we get :

At first,Area of parallelogram = 1/2 × base × altitudeArea = 1/2 × AB × CEArea = 1/2 × 30 × 14★Area = 210 {cm}^{2}Area=210cm 2 ★Secondly,Area of parallelogram= 1/2 × base × altitudeArea = 1/2 × AD × BFArea = 1/2 × AD × 20★Area = 10AD{cm}^{2}Area=10ADcm 2 ★Equaling both we get :10AD{cm}^{2}=210{cm}^{2}10ADcm

At first,Area of parallelogram = 1/2 × base × altitudeArea = 1/2 × AB × CEArea = 1/2 × 30 × 14★Area = 210 {cm}^{2}Area=210cm 2 ★Secondly,Area of parallelogram= 1/2 × base × altitudeArea = 1/2 × AD × BFArea = 1/2 × AD × 20★Area = 10AD{cm}^{2}Area=10ADcm 2 ★Equaling both we get :10AD{cm}^{2}=210{cm}^{2}10ADcm 2

At first,Area of parallelogram = 1/2 × base × altitudeArea = 1/2 × AB × CEArea = 1/2 × 30 × 14★Area = 210 {cm}^{2}Area=210cm 2 ★Secondly,Area of parallelogram= 1/2 × base × altitudeArea = 1/2 × AD × BFArea = 1/2 × AD × 20★Area = 10AD{cm}^{2}Area=10ADcm 2 ★Equaling both we get :10AD{cm}^{2}=210{cm}^{2}10ADcm 2 =210cm

At first,Area of parallelogram = 1/2 × base × altitudeArea = 1/2 × AB × CEArea = 1/2 × 30 × 14★Area = 210 {cm}^{2}Area=210cm 2 ★Secondly,Area of parallelogram= 1/2 × base × altitudeArea = 1/2 × AD × BFArea = 1/2 × AD × 20★Area = 10AD{cm}^{2}Area=10ADcm 2 ★Equaling both we get :10AD{cm}^{2}=210{cm}^{2}10ADcm 2 =210cm 2

At first,Area of parallelogram = 1/2 × base × altitudeArea = 1/2 × AB × CEArea = 1/2 × 30 × 14★Area = 210 {cm}^{2}Area=210cm 2 ★Secondly,Area of parallelogram= 1/2 × base × altitudeArea = 1/2 × AD × BFArea = 1/2 × AD × 20★Area = 10AD{cm}^{2}Area=10ADcm 2 ★Equaling both we get :10AD{cm}^{2}=210{cm}^{2}10ADcm 2 =210cm 2

At first,Area of parallelogram = 1/2 × base × altitudeArea = 1/2 × AB × CEArea = 1/2 × 30 × 14★Area = 210 {cm}^{2}Area=210cm 2 ★Secondly,Area of parallelogram= 1/2 × base × altitudeArea = 1/2 × AD × BFArea = 1/2 × AD × 20★Area = 10AD{cm}^{2}Area=10ADcm 2 ★Equaling both we get :10AD{cm}^{2}=210{cm}^{2}10ADcm 2 =210cm 2 Or, 10AD = 210

Or, AD = 210/10 cm

Or, AD = 210/10 cm★ AD = 21 cm★

Or, AD = 210/10 cm★ AD = 21 cm★\large\boxed{AD=21\:cm}

Or, AD = 210/10 cm★ AD = 21 cm★\large\boxed{AD=21\:cm} AD=21cm

Or, AD = 210/10 cm★ AD = 21 cm★\large\boxed{AD=21\:cm} AD=21cm

Or, AD = 210/10 cm★ AD = 21 cm★\large\boxed{AD=21\:cm} AD=21cm

Or, AD = 210/10 cm★ AD = 21 cm★\large\boxed{AD=21\:cm} AD=21cm Hope it helps you ♥ ♥ ♥

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