Question

In figure 7.31, radius of circle is 7cn and m(arc MBN)=60°,find
Area of circle
A(O-MBN)
A(O-MCN)​

Answer 1

Area of sector MBN =

$\pi \: r {}^{2} \times angle \div 360$

$3.14 \times 7 {}^{2} \times 60 \div 360$

= 25.64 sq cm