Question

In figure 7 D is the midpoint of BC . DP perpendicular to AB, DQ perpendicular to AC and DP =DQ prove that angle b = angle c .

please fast its urgent!!

Answer 1

In DPB & DQC
angle p=angleq
bd=dc
pb=qc.

by RHS congruence rule both are congruent
by CPCT
B=C

Answer 2

Answer:

Step-by-step explanation:

We can prove this by the congruency of two triangles.

Between Δ PBD and Δ QCD,

PD = QD                                   (Given/Data)

m∠BPD = m∠CQD                    (=90°)

BD = CD                                    (D is the midpoint of BC)

From this, ΔBPD ≅ ΔCQD and BPD⇔ CQD is a congruency. (By RHS postulate)

∴∠B ≅ ∠C                             (By CPCT)

Thank you :) <3