Question

In figure 8.107 AB || CD || EF and GH || KL find angle HKL

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

The angle of HKL is $145^0$

Step-by-step explanation:

Step 1:

Produce LK to meet GF at N.

Now, alternate angles are equal.

Step 2:

∠ CHG= ∠ HGN =  $60^0$

∠ HGN = ∠ LNF = $60^0$ (corresponding angles).

Step 3:

Therefore ∠ KNG= $180^0 - 60^0 = 120^0$

∠ GNK= ∠ AKL = $120^0$ (corresponding anlges)

∠ AKH = ∠ KHD = $25^0$ (alternate angles)

∠ HKL= ∠ AKH + ∠ AKL  =$25^{0} + 120^0 = 145^0$