In figure 8.6 , find angle ABC and angle A and write which of triangle ABC are equal.
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1
Answer:
Angle BAC is 50° and angle ACB is 50°
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Answered by
2
Answer:
Let the given triangle be ABC such that ∠ABC=36. A line through C meets AB at D.
Now, In △DBC,
DB=DC (Given)
hence, ∠DBC=∠DCB=36
∘
(Isosceles triangle property)
Sum of angles of triangle = 180
∠DBC+∠DCB+∠CDB=180
36+36+∠CDB=180
∠CDB=108
Now, ∠ADC=180−∠ADB
∠ADC=180−108
∠ADC=72
∘
in △ADC,
∠ADC=∠DAC=72
∘
(Isosceles triangle property, AC= CD is given)
Sum of angles = 180
∠ADC+∠CAD+∠ACD=180
72+72+x=180
x=180−144
x=36
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