Question

in figure 8.6 find angle ACB and Angle A and write which sides of angle abc are equal

Answer 1

As angle ABC and angle ACB forms linear pair =180°
angle ACB= 180-130=50°
In triangle ABC, angle A = 180-50-80=50

Answer 2

Answer: angle acb + 130=180(linear pair)

Acb =180-130=50

Acb=50

Angle a:

A+b+c=180(angle sum property)

A+80+50=180

A+130=180

A=180-130

A=50

Thanks