In Figure 8, AB = DC and BC=AD.
Is triangleABC congurant to triangleCDA?
Justify your answer.
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Step-by-step explanation:
Given
AB=DC and BC=AD
To prove
∆ABC congruent to ∆CDA
Proof
Given that AB=DC and BC=AD
So, ABCD is a parallelogram
we know that diagonal of a parallelogram divides it into two congruent triangles
therefore AC divides palagram ABCD into two congruent triangles
i.e ∆ABC≅∆CDA (PROVED)
OR
Consider ∆ABC and ∆CDA
AB=CD (Given)
BC=AD (Given)
AC=AC (Common)
So, ∆ABC ≅∆CDA (By SSS criteria)
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