In Figure-8, ABCD is a parallelogram. A semicircle with centre O and the
diameter AB has been drawn and it passes through D. If
AB = 12 cm and OD 1 AB, then find the area of the shaded region
(Use n = 314)
(93-7
Figure-8
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In Figure-8, ABCD is a parallelogram. A semicircle with centre O and the diameter AB has been drawn and it passes through D. When AB = 12 cm and OD 1 AB, then the area of the shaded region is 7.74 cm^2.
Given,
AB = 12 cm
OA = OB = OD = AB/2
= 12/2 = 6cm
Area of shaded portion = Area of parallelogram - Area of quadrant
Area of shaded portion = b × h - (pi × r^2) / 4
= OB × OD - 3.14 × OD^2/4
= 6 × 6 - 3.14 × 6^2/4
= 36 - 28.26
= 7.74 cm^2
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