Question

In Figure-8, ABCD is a parallelogram. A semicircle with centre O and the
diameter AB has been drawn and it passes through D. If
AB = 12 cm and OD _I_ AB, then find the area of the shaded region.
(Use
$\pi = 3.14$
​

Answer 1

Answer:

Here O is center, hence AO=OB=6cm

Now,

Ar(shaded =ar(ll^gm) - ar(quardrant)

region)

=bh-22/7 *1/4*36

=12*6-11/7*18

=72-11(2.57)

=72-28.27

=43.73 cm^2

Hope this helps you.

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