Question

in figure 9.44 ABC is an isosceles triangle in which AB = AC also D is a point such that BD=CD prove that AD bisects angle /_A and/_ d​

Answer 1

Step-by-step explanation:

in the above figure the given info AB= AC

BD=DC

and AD =AD (common side)

so by sss congruence we can say that triangles ABD is congruent to triangle ACD

so by cpct

we can say that angle BAD = CAD

and angle BDA= CDA

so that means AD bisecting the angle A and angle D

hence proved