In figure a) and b), find the values of m, n and o.
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Answers
Answer:m = 100
Step-by-step explanation:Three angles are equal = 180
A + C + D = 180
50+ 80+O= 180
130 +O = 180
O = 180- 130
O = 50
THEN
O = D = 50
A+ B +D = 180
30 + m+ 50 =180
80 + m = 180
m = 180- 80
m = 100
Same formula use in B part
a) Given:
- ∠BAD = 30°
- ∠ACD = 80°
- ∠DAC = 50°
To Find:
- Values of m, n and o = ??
Solution:
To find o = ??
∠DAC + ∠ACD + ∠CDA = 180° [Angle sum property of triangle]
50° + 80° + o° = 180°
130° + o° = 180°
o° = 180° - 130°
o° = 50°
To find m = ??
∠BDA + ∠CDA = 180° [Linear pair]
m° + 50° = 180°
m° = 180° - 50°
m° = 130°
To find n = ??
∠BAD + ∠ADB + ∠DBA = 180° [Angle sum property of triangle]
30° + 130° + n° = 180°
160° + n° = 180°
n° = 180° - 160°
n° = 20°
Hence, value of m = 130, n = 20 and o = 50
____________________
b) Given:
- ∠QPS = 65°
- ∠PQS = 50°
- ∠PRS = 40°
To Find:
- Values of m, n and o = ??
Solution:
To find m = ??
∠PQS + ∠QPS + ∠PSQ = 180° [Angle sum property of triangle]
50° + 65° + m° = 180°
115° + m° = 180°
m° = 180° - 115°
m° = 65°
To find n = ??
∠PSQ + ∠PSR = 180° [Linear pair]
65° + n° = 180°
n° = 180° - 65°
n° = 115°
To find o = ??
∠SPR + ∠PSR + ∠PRS = 180° [Angle sum property of triangle]
o° + 115° + 40° = 180°
o° + 155° = 180°
o° = 180° - 155°
o° = 25°