Question

In figure A, B and C are three points on a circle with centre O such that \angle BOC = 30º and \angle AOB = 60º. If D is a point on the circle other than the arc ABC, find \angle ADC

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Answer 1

Answer:

∠ADC=45º

Step-by-step explanation:

∠AOC=∠AOB+∠BOC

=60º+30º

=90º

Arc ABC subtends ∠AOC at centre of a circle.

∠AOC=2∠ADC  

90º=2∠ADC

∠ADC=45º

HOPE IT HELPS!!!

Answer 2

Answer:

✏AOC => ∠AOB +∠BOC

=> 60° + 30°

=> 90°

✏Arc ABC subtends ∠AOC at centre of a circle.

And ∠ADC on point D

✏therefore ;

∠AOC=2∠ADC (Angle subtended by arc at the centre is double the angle subtended by it at any point on circumference. )

90° => 2∠ADC

✔∠ADC => 45 °✔

Hope it helps you dear.....

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