In figure A, B and C are three points on a circle with centre O such that \angle BOC = 30º and \angle AOB = 60º. If D is a point on the circle other than the arc ABC, find \angle ADC
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Step-by-step explanation:
Hello! sis à very very Ğood Mõõrning to u..✌
This is your answer (^___^)
AOC=∠AOB+∠BOC
=60∘+30∘
=90∘
Arc ABC subtends ∠AOC at centre of a circle.
And ∠ADC on point D
therefore
∠AOC=2∠ADC (Angle subtended by arc at the centre is double the angle subtended by it at any point on circumference. )
90∘=2∠ADC
∠ADC=45∘
Hope this may helps u..
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