Question

In figure A, B and C are three points on a circle with centre O such that \angle BOC = 30º and \angle AOB = 60º. If D is a point on the circle other than the arc ABC, find \angle ADC​

Answer 1

Step-by-step explanation:

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This is your answer (^___^)

AOC=∠AOB+∠BOC

=60∘+30∘

=90∘

Arc ABC subtends ∠AOC at centre of a circle.

And ∠ADC on point D

therefore

∠AOC=2∠ADC     (Angle subtended by arc at the centre is double the angle subtended by it at any point on circumference. )

90∘=2∠ADC

∠ADC=45∘

Hope this may helps u..