Question

In figure A, B, and D are four points on a circle. AC and BD intersects are a point E. such that angle BEC = 130 ° and angle ECD = 20 . Find angle BAC. ​

Answer 1

Answer:

ANSWER

∠BEC+∠DEC=180°

(complimentary angles)

130 °

+∠DEC=180 °

∠DEC=50 °

In ΔDEC -

∠DEC+∠ECD+∠CDE=180°

∠CDE=110°

by theorem of circles -

∠BAC=∠CDE

∴∠BAC=110°

Answer 2

Answer:

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