in figure a b c and d are concyclic points angle dbc =30,angle DCB=70 find angle BAC please help me
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your answer..
in ΔBDC
angle DBC + angle BCD + angle BDC = 180
30 + 70 + angle BDC = 180
100 + angle BDC = 180
angle BDC = 180 - 100 = 80°
angle BDC = angle BAC ( angle in same segment)
angle BAC = 80°✔✔
hope it helps...
your answer..
in ΔBDC
angle DBC + angle BCD + angle BDC = 180
30 + 70 + angle BDC = 180
100 + angle BDC = 180
angle BDC = 180 - 100 = 80°
angle BDC = angle BAC ( angle in same segment)
angle BAC = 80°✔✔
hope it helps...
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