Question

in figure A , B C and D are four points on a circle AC and BD intersect at a point E such that <BEC =130• and <ECD =20• Find < BAC the attachment is given upward ​

Answer 1

Answer:

<BAC=110°

Step-by-step explanation:

<DEC= 180-130= 50°

<DEC=<AEB=50°

<EDC= 180-<DEB-<DCE

= 180-50-20

=180-70

<EDC=110°

<BAC=<EDC=110° ( because both angles are subtended fron the same chord BC)

<BAC=110°

Answer 2

hope it's help u.....tc....