Question

In figure, a circle inscribed in triangle ABC touches its sides AB, BC and AC at points D,

E and F respectively. If AB = 12 cm, BC = 8 cm and AC = 10 cm, then find the lengths of

AD, BE and CF.​

Answer 1

ANSWER

We know that AD= AF

BD=BE

CE=CF

Let AD= AF=x

BD=BE=y

CE=CF=z

Then x+y=12

y+z=8

x+z=10

On Solving above equation we get x=7,y=5,z=3

So AD=7 , BE=5 , CF= 3