Question

. In figure, a circle touches the side BC of ∆ABC at P and touches

AB and AC produced at Q and R respectively. If AQ = 5 cm, find the

perimeter of ∆ABC.

​

Answer 1

Answer:

Thelengthsofthetangents,fromapointtoacircle,areequal.

Therefore AB = AP,  BQ = BP, BP = CP

Perimeter = AC + AB + BC = 2(AB) + BP + PC = 2(AB) + 2(BQ) = 2(AQ) = 30 cm

Step-by-step explanation:

please follow me