Question

in figure a parallelogram is drawn in a trapezium the area of a parallelogram to 80 cm in the area of trapezium​

Answer 1

those who solve this maths ans in 7 minutes I will give u brainliest and lost of thank pls solve this in long then only I will give

Answer 2

Answer:

Area of the trapezium $= 128 cm^2$

Step-by-step explanation:

The triangle left when the parallelogram is cut off from the trapezium, must have the base = 22cm - 10cm = 12 cm.  [∵ opposite sides of parallelogram are equal]

The same triangle have other two sides = 10 cm each

Therefore, perimeter of the triangle = (12 + 10 + 10) cm = 32 cm.

Half the perimeter, S = 32/2 cm = 16 cm

Therefore, s(s - a)(s - b)(s - c) = 16(16 - 12)(16 - 10)(16 - 10) = 16x4x6x6 = 48x48

∴ $\sqrt{s(s - a)(s - b)(s - c)} = \sqrt{4^2.12^2} cm^2 = 48 cm^2$

Area of the trapezium = Area of the parallelogram + Area of the triangle

$= 80 cm^2 + 48 cm^2 = 128 cm^2$