Math, asked by anusubh234, 10 months ago

in figure a path 2.5 metre wide runs along inside the boundary of a square field whose each side is 65m. the path is to be covered with the red gravel and the rest of the field is to be manured. find the total expenses involved if the cost of covering the path with red gravel is rupees 1.50 per m square and that that of manuring the field rupees 0.50 per metre square.​

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Answers

Answered by Anonymous
9

Area of the path = 861 m² .

Step-by-step explanation:

Given :-

→ Width of path = 3.5 m .

→ Side of square park along with path = 65 m .

To find :-

→ Area of the path .

Solution :-

∵ Side of square park without the path = 65 - ( 2 × 3.5 )  =  58 m .

Now, area of square park alnog with path

= side × side .

= ( 65 × 65 ) m² .

= 4225 m² .

And, area of square park without path

= side × side .

= ( 58 × 58 ) m² .

= 3364 m² .

Therefore, area of the path = ( 4225 - 3364 ) m² .

= 861 m² .

And, cost of measuring the rest of the field = 3364 × 25 .

= ₹86100 .

Hence, it is solved .

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Answered by priyagupta1153
3

Area of the path = 861 m² .

Step-by-step explanation:

Given :-

→ Width of path = 3.5 m .

→ Side of square park along with path = 65 m .

To find :-

→ Area of the path .

Solution :-

∵ Side of square park without the path = 65 - ( 2 × 3.5 ) = 58 m .

Now, area of square park alnog with path

= side × side .

= ( 65 × 65 ) m² .

= 4225 m² .

And, area of square park without path

= side × side .

= ( 58 × 58 ) m² .

= 3364 m² .

Therefore, area of the path = ( 4225 - 3364 ) m² .

= 861 m² .

And, cost of measuring the rest of the field = 3364 × 25 .

= ₹86100 .

Hence, it is solved .

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