In figure a spherical part of radius r/2 is removed
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Answered by
3
Answer:
ur answer is here
Explanation:
Let the centre of the big sphere which is its centre
of mass be the origin O. Then the centre of mass
of the small sphere is at a distance R/2 from O.
When the small sphere is cut out, let the C.M. of the
remaining portion shifts to P. Mass of remaining portion = 3M/4.
From conservation of centre of mass :
C.M. of remaining portion = C.M. of big sphere + C.M. of the small sphere.
⇒
4
3M
×(−OP)=M×OO+
4
M
×
2
R
⇒OP=−
6
R
so,thecenterofmassofremainingportionshiftsto
6
R
fromcentreofthecircle.
hope u you understood better from it
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Answered by
0
Answer:
dont know the answer.....sry
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