Physics, asked by GSSSGFGH8777, 10 months ago

In figure a spherical part of radius r/2 is removed

Answers

Answered by Sakshisharma2810
3

Answer:

ur answer is here

Explanation:

Let the centre of the big sphere which is its centre

of mass be the origin O. Then the centre of mass

of the small sphere is at a distance R/2 from O.

When the small sphere is cut out, let the C.M. of the

remaining portion shifts to P. Mass of remaining portion = 3M/4.

From conservation of centre of mass :

C.M. of remaining portion = C.M. of big sphere + C.M. of the small sphere.

4

3M

×(−OP)=M×OO+

4

M

×

2

R

⇒OP=−

6

R

so,thecenterofmassofremainingportionshiftsto

6

R

fromcentreofthecircle.

hope u you understood better from it

thanks✌

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Answered by ishu2810
0

Answer:

dont know the answer.....sry

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